average Model Questions & Answers, Practice Test for ibps clerk prelims
Average score of Rahul, Manish and Suresh is 63. Rahul’s score is 15 less than Ajay and 10 more than Manish. If Ajay scored 30 marks more than the average scores of Rahul, Manish and Suresh, what is the sum of Manish’s and Suresh’s scores ?
Answer: (a)
Let the score of Ajay = x
Rahul = x – 15
Manish = x – 25
According to question,
x = 63 + 30 ⇒ x = 93
∴ Score of Ajay = 93
then Rahul = 93 – 15 = 78
then Manish = 93 – 25 = 68
Total marks of Rahul, Manish and Suresh
= 3 × 63 = 189
∴ Suresh = 189 – (78 + 68) = 43
∴ Manish + Suresh = 68 + 43 = 111
The mean of 20 observations is 17. On checking it was found that the two observations were wrongly copied as 3 and 6. If wrong observations are replaced by correct values 8 and 9, then what is the correct mean ?
Answer: (c)
Mean of 20 observation = 17
total sum = 17 × 20 = 340
ATQ ${340 - 3 - 6 + 8 + 9}/20 = 348/20$ = 17.4
The average market price of three shares x, y and z is Rs. m. Shares x and y lose Rs. n each and z gains Rs. $n/2$. As a result, the average market price of the three shares decrease by Rs. 1. The value of n is
Answer: (c)
The net decrease in the average can be expressed as
${y + y - (y/2)}/3 = 1$ ⇒ y = 2
The average of 5 consecutive even number A, B, C, D and E is 34. What is the product of B and D?
Answer: (d)
Let A = x,
According to the question,
∵ A + B + C + D + E
= x + (x + 2) + (x + 4) + (x + 6) + (x 8)
5x + 20 = 34 × 5 = 170
B × D = 32 × 36 = 1152
The average of six numbers is 3.95. The average of two of them is 3.4, while the average of the other two is 3.85. What is the average of the remaining two numbers?
Answer: (b)
Sum of the remaining two numbers
= (3.95 × 6) – [(3.4 × 2) + (3.85 × 2)]
= 23.70 – (6.8 + 7.7) = 23.70 – 14.5 = 9.20
∴ Required average = $(9.2/2) = 4.6$
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